Pointer and Array

Question

What is the output of the above program?

Explanation:

(*(*(*p)[1]-2)) = E 
(*(*(*p)[0]+1)) = A 
E - A = 4 

Answer 1

Here is some sort of explanation 

Comments

Thank you @Aehkn Junior

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i have one doubt, *(p)[1] can be written as *(p+0)[1] which can be further written as p[0][1],,so how is it address of U?

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*(p)[1] does not equal p[0][1]. Braces have higher priority than the dereference operator. So *(p)[1] means *((p)[1]) and p[0][1] means (*(p))[1].

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ok..got it,thanks..:-)