Answer is option D in both questions.
$0.239 = (0.00111101)_2$
(a) Stored exponent = actual + biasing
$13 + 64 = 77$
$(77)_{10} = (1001101)_{2}$
Answer is: $\underbrace{0}_{\text{sign}}\;\underbrace{1001101}_{\text{exponent}}\;\underbrace{00111101}_{\text{mantissa}} =\text{0x 4D 3D}$
(b) For normalized representation
$0.00111101 *2^{13} = 1.11101 *2^{10}$
Stored exponent $= 10+64=74$
$(74)_{10} =(1001010)_{2}$
Answer: $\underbrace{0}_{\text{sign}}\;\underbrace{1001010}_{\text{exponent}}\;\underbrace{11101000}_{\text{mantissa}}=\text{0x 4A E8}$ .