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(a) If $R$ is regular and $N$ is non-regular, then there exists $R+N$, which is regular.

(b) If $R$ is regular and $N$ is non-regular, then there exists $R+N$, which is non-regular.
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what is + on a set? does it stand for union?
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yes..it is union
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dont know what is + sign here because R and N used as SET.

if it is Union then ,

1. R= (a+b)*, N = a^nb^n , n>=0

R U N = (a+b)* which is regular.

2.R = phi, N = a^nb^n, n>=0

R U N = a^nb^n, n>=0

 

both are true (bcoz in options they said THERE EXIST )

(in general both are true but for a particular case where L and N is precisely given it may not holds true).
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r1+r2=l1 unioin l2
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