2NF decomposition

Question

How is it option D??

Answer 1

option d

Answer 2

Here candidate keys are AB ,BC and F.

There is partial dependency in FD ( B->D ).

I think C->A is not partial dependency ,since A is key attribute.

So to eliminate that divide the table into two tables as

take B+ = { B,D,E } as one table and remaining as others and B is the common attribute .

So (ABCF) , (BDE) .

Correct if anything wrong.

Comments

okay.

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Why there is a need to take closure of B....we can go with option B as B->D is only relation having PD ??

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It's right ans