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Question

main()

{

int a;

scanf("%i"&a);

printf("%i %d",a,a);

scanf("%d",&a);

printf("%i %d",a,a);

}

suppose user entered 0x56 as input  .what is printed by above program?

Answer 1

Same way here it recognizes hexadecimal value so outputs are

86 86

0 0

as decimal will see 0x56 so it will only take 0 as decimal value.

Comments

it means as there is any character encountered scanf stops reading further?