let N13 -> # of 3 digits nos. divided by 13
let N11 -> # of 3 digits nos. dvided by 11
N11 $\cup$ N13 = N11 + N13 - N11$\cap$N13
= 81 + 69 - 6 = 144
total 3 digits # which are neither multiple of 11 nor 13 = total nos(3 digits) - N11 $\cup$ N13
= 900 - 144 = 756