total memeory location = 2^12
Number of data lines (word size) = 8 Number of address lines = 7 Total number of addressable memory locations/number of memory words = $2^{7}$ = 128
The number of data lines just gives the word size.
Thus, the answer should be $2^{7}$
Although, if the que. was size of the chip, it is given by $128 * 8 = 2^{10}$
Ref : https://books.google.co.in/books?id=AIHgbyyEIHoC&pg=RA1-SA6-PA1&dq=number+of+data+lines+gives+word+size&hl=en&sa=X&ved=0ahUKEwir6qDGlO3oAhWPbysKHeLXBAcQ6AEIKjAA#v=onepage&q=number%20of%20data%20lines%20gives%20word%20size&f=false
Given data, address line=7 Data lines=8 Chip selected lines=2 Step-1: Total address lines are 2^7 and chips select lines Step-2: The chips select lines are 2^2 Step-3: Total address and chip selected lines are 2^7 * 2^2 = 2^9 Step-4: Number of memory locations for 8 data lines =2^9 * 2^3 = 2^12
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