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Consider a network connecting two systems, ‘A’ and ‘B’ located 6000 km apart. The propagation speed of media is 2 × 106 mps. It is needed to design a Go-Back-7 sliding window protocol for this network. The average packet size is 107 bits. If network used as its full capacity, then the bandwidth of network is__________ Mbps

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is it 107 ?

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I got the same but the given answer is 105 Mbps.
Actually they have taken the window size as 127. I just don't understand why.
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But if we take bandwidth as 105 Mbps then, 1+2a = 64 i.e window size should be 64. Correct me if I am wrong
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Absolutely right. I didn't notice it.
They have done the wrong calculation.
But what should be he window size?

This is the given solution.

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