computer network

Question

what is differential equation in this

Answer 1

A = KP(1-P)^K-1 
dA/dP  = 0
==> K[ P* (K-1)*(-1)*(1-P)^K-2 + (1-P)^K-1 ] =0
==> P*(K-1)=[(1-P)^K-1 / (1-P)^K-2] 
==> P* (K-1) = 1-P
==> PK-P = 1-P
==> P=1/K
 

A=KP(1-P)^K-1
A=K * 1/K  (1-1/K)^K-1
A= (1-1/K)^K-1

Now if K tends to infinity
$\lim_{K ->\infty} (1-1/K)^{K-1}$
It is of the form 1 ^ infinity 
solving we get 1/e 

Comments

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