Function

Question

swap(int c, int d)
{
    int k,t;
    k=3;
    t=c;
    c=d;
    d=t;
    k=c+d+t;
}
main()
{
    int k=5, l=9;
    swap(k,l);
    printf("%d,%d",k,l);
}

• A. 9,5
• B. 5,9
• C. 5,19
• D. 19,5

Comments

5 and 9

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plz explain ??

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Here we use simply " Call by Value method"  ,so there is no change in Actual Parameter.

so option B : 5,9  is right

Answer 1

$printf$ will print the value which the $swap$ function returns

& we can clearly see that the $swap$ function didn't return anything

So, $printf$ will print the argument of $swap$ i.e. $k=5$, $l=9$

Answer 2

Answer is option(d)