ISRO2018-60

Question

What is the output of tho following program?

main(){
    int x=2, y=5;
    if(x<y) return (x=x+y);
            else printf("z1");
    printf("z2");
}

• A. $z2$
• B. $z1z2$
• C. Compilation error
• D. None of these

Comments

option D is correct.

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yes the answer is correct. option D.

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why “ printf("z2");” is not executed?

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Returning int without specifying return type is a compiler error since c99.

https://stackoverflow.com/questions/30542092/function-without-return-type-specified-in-c

Answer 1

No output if condition is true and value x is returned

Answer 2

ANSWER: D NONE OF THESE

plz run this:

#include<stdio.h>
int main()
{
   int x=2,y=5;
   if(x<y)
   {
      return (x=x+y);
   }
   else
   {
      printf("z1");
   }
   printf("z2");
}