ISRO2018-60

Question

What is the output of tho following program?

main(){
    int x=2, y=5;
    if(x<y) return (x=x+y);
            else printf("z1");
    printf("z2");
}

• A. $z2$
• B. $z1z2$
• C. Compilation error
• D. None of these

Comments

option D is correct.

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yes the answer is correct. option D.

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why “ printf("z2");” is not executed?

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Returning int without specifying return type is a compiler error since c99.

https://stackoverflow.com/questions/30542092/function-without-return-type-specified-in-c

Answer 1

This code will first replace value of variable x by (5+2)=7 because x<y.Then x will return it's current value 7.So no output will be printed.i.e option D is correct.

Comments

https://ideone.com/9XlV6U

It throws runtime error

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https://onlinegdb.com/rkzf6QNpf

Not always

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Use standard c compiler

Answer 2

answer is (D)

Answer 3

option D is correct

Answer 4

None of these. (D)
Runtime Error

Comments

can anyone explain why it is not showing any output?

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because of return statement. it terminates the code. in the code was like

#include<stdio.h>

int main (){

int x=2, y=5;

if (x<y) return printf(“%d”,x+y);

else printf(“z1”);

printf(“z2”);

}

in the above case the output will be 7 because once the “return” function is executed, the whole code will be terminated.