A particular disk unit uses a bit string to record the occupancy or vacancy of its tracks, with $0$ denoting vacant and $1$ for occupied. A $32$-$bit$ segment of this string has hexadecimal value D4FE2003. The percentage of occupied tracks for the corresponding part of the disk, to the nearest percentage is:
Bit String: $D4FE2003: 1101\ 0100\ 1111 \ 1110\ 0010 \ 0000 \ 0000 \ 0011$
Number of vacant tracks: 18
Number of occupied tracks:14
Percentage occupied tracks: $\frac{14}{32}*100=43.75 \% \simeq44\% $
Option d) is correct
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