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C,.  because T(n)=aT(n/b)+f(n)

      Where f(n) is polynomial fn

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dhingrak asked Jan 18, 2015
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When do we say that 2 functions are polynomially comparable for applying master theorem...? We can apply the theorem for T(n)=3T(n/4)+nlgn but cant apply it for T(n)=2T(n...