consider a sender sends 12 segments to a receiver.The RTD between the sender and receiver is 1 msec.The transmission time of each frame is 0.1 msec .The timeout value is 2 msec and there are no negative acknowledgement.In each of the following cases,how does it take for sender to transfer the 12 segments.
(A)If stop and wait protocol is used.The 3rd and 6th segments are corrupted.The 7th segment is lost.
(B)if Go-Back-N protocol is used.The window size is 4.The 2nd segment is corrupted.The 4th and the 6th segments are lost during the first transmission.
