0 votes 0 votes ${(a+aa+b)}^{+}={(a+b)}^{+}$ Theory of Computation theory-of-computation regular-expression + – Dhananjay15 asked Aug 19, 2018 • retagged Oct 4, 2022 by Shubham Sharma 2 Dhananjay15 601 views answer comment Share Follow See 1 comment See all 1 1 comment reply Shaik Masthan commented Aug 20, 2018 reply Follow Share (a+aa+b)+ = remove aa due to a+ can form it 1 votes 1 votes Please log in or register to add a comment.
1 votes 1 votes Both of them are same. Swapnil Naik answered Aug 20, 2018 Swapnil Naik comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Proof using Identities: abhinowKatore answered Oct 3, 2022 abhinowKatore comment Share Follow See all 0 reply Please log in or register to add a comment.
