The number of positive integers $n$ for which $n^3 +(n+1)^3 +(n+2)^3 = (n+3)^3$ is
n3 + (n+1)3 + (n+2)3 = (n+3)3
n3 +( n3 + 3n2 +3n +1)+(n3 + 6n2 +12n +8) = n3 + 9n2 +27n +27
n3 - 6n -9=0
n(n2-6)=9
only n=3 satisfy above equation
Ans : B
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