in Mathematical Logic
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no of ways to select 22 people out of 40 people for cricket team of 11 each
in Mathematical Logic
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4 Comments

@shaik

I think it will be

$\binom{40}{11} * \binom{29}{11}$ if teams are numbered

and

$[ \binom{40}{11} * \binom{29}{11}]/2$ if teams aren't numbered.

Take a small example like two teams from 4 people with 2 members each.
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thank u @smsubham for correcting me

yes you are right !

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if you  select 22 from 40 then 11 from 22 & 11 from remaining 11 (that would be only 1one way) then also you would get the right answer..

Both the ways will give right answer & final answer would be like 40!/18!*11!*11!*2!

for unumbered teams
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