General Topic Doubt General Aptitude: Numerical Ability

Question

What is the smallest number that when divided by 12, leaves 10, when divided by 16, leaves 14 and when divided by 24, leaves 22 as a remainder?

Comments

@Deepanshu,@Shaijal Tripathi,Both of you please work out the steps.

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@If I m not wrong by adding the remainders 10,14 and 22 we get 46 as as the answer. Also, the LCM of the numbers is 48. The no 2 has to be subtracted from it. Is it the right way that I m approaching?

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I JUST DID IT BY HIT AND RUN SO I AM NOT GOOD TO ANSWER THIS . : )

Answer 1

The answer is as follows:-

Method goes as follows:-

The LCM of 12,16 and 24 is 48. Now on a common observation it is found that 12-10=2,16-14=2 and 24-22=2. So in a way the divisors are n+2 than the remainder. The common divisor. Therefore the least number will be 48-2=46. This is how the ans is reached.

Comments

Yes, just like you've done :)

Answer 2

This is how I solved it.