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Locate the inflection points and region where f(x) is concave up or down
f(x)=$-x^3+x^2+x$
in Calculus
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f(x)=−x3+x2+x

f'(x) = -3x2 + 2x +1

f'' (X) = -6x+2

f'' (X) = 0

x = 1/3

we know that if f''(x) < 0 means it's maximum therefore it's concave down

similarly if f''(x) >0 means it's minimum therefore it's concave Up

f(x) is concave up (- $\infty$ ,1/3)

f(x) is concave down (1/3 , +  $\infty$ )

Point of inflection : f(1/3) = 11/27

therefore point of inflection : (1/3 , 11/27)

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aditi19 asked in Calculus Oct 25, 2018
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