The network consists of 4 hosts distributed as shown below: Assume this network uses CSMA/CD . And signal travels at $3$ $X$ $10^{5} \text{km/sec}$
If sender sends at $1 \text{Mbps}$. What could be the minimum size of packet?
(a).$600$ $\text{bits}$
(b). $400$ $\text{bits}$
(c). $6000$ $\text{bits}$
(d). $1500$ $\text{bits}$
The minimum size of packet in CSMA/CD is TT>=2*TP. Length of packet=2*(distance/Speed of signal)*Bandwidth. Here all terms are common b/w all nodes except distance. So minimum the distance, minimum will be length of packet. Here minimum distance=40km L=2*(40/3*105)*106=800/3=266.66 bits
64.3k questions
77.9k answers
244k comments
80.0k users