Statement 1 is false.
Consider f(n) = 0.5 and g(n) = sin(n)
or, consider f(n) = n and g(n) = 1 when n is even; $n^{2}$ when n is odd.
In both the above cases neither f(n) = Og(n) nor g(n) = Of(n)
Statement 2 is false
Consider g(n) = 2n and h(n) = n and f(n) = 10n
Other important statements
All the below cases are possible:-
$f(n) = Og(n)$ and $g(n) = Of(n)$ — Case 1
$f(n) = Og(n)$ and $g(n) \neq Of(n)$ — Case 2
$f(n) \neq Og(n)$ and $g(n) \neq Of(n)$ — Case 3
Case 1
When f(n) and g(n) are identical both functions can upper bound each other.
Case 2
f(n) = n and g(n) = $n^{2}$
Case 3
See "Statement 1 is false"