Self Doubt

Question

A.2^(loglogn)^2,

B.(2^(root(logn))

Asymptotic Order

Comments

no check the same for 2^1024 or some higher than it .

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Abhisek Tiwari 4

See solution now.

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just see this, even i was confused in these 2 options only;

taking double log;

$=2^{(loglogn)^{2}}  =(loglogn)^{2} =2logloglogn$

$=2^{\sqrt{logn}}=\sqrt{logn}= 0.5loglogn$

now  $2^{\sqrt{logn}}$ is larger!!

pls confirm someone!!