NIELIT 2018-56

Question

Identify the total number of tokens in the given statement

printf("A%B=",&i);

• A. $7$
• B. $8$
• C. $9$
• D. $13$

Answer 1

"A%B=" is counted as one so total tokens are 8

1. printf

2. (

3. "A%B="

4. ,

5. &

6. i

7. )

8. ;

Comments

There’s no comma in the given statement.

---

NO sir

Answer 2

$\textrm{Total number of token is 7 here.}$

1. $printf$
2. $($
3. $\textrm{”A%B”}$
4. $\textrm{&}$
5. $i$
6. $)$
7. $;$

$\textrm{Option A }$

Comments

Why haven’t you considered comma in this question ?

Answer 3

the tokens are:

1. printf - a function that prints output to the console
2. ( - left parenthesis
3. "A%B=" - a string literal
4. , - a comma
5. & - the address-of operator
6. i - a variable
7. ) - right parenthesis

The semicolon at the end of the statement is not a token. It is a statement terminator that indicates the end of the statement in C-style languages.

Answer 4

I See that people are merely justifying the answers key with 7 tokens, but the real answer is going to be 8 tokens.

Someone missed comma, someone says semicolon is not included etc; ignore them and see the official grammar of C  - both $comma$ and $semicolon$ are valid tokens.

Here is breakdown for all 8 tokens in the statement :

Tokens and Their Values

Token Category	Token Number	Token Value
identifier	1	'printf'
l_paren	2	'('
string_literal	3	'"A%B="'
comma	4	','
amp	5	'&'
identifier	6	'i'
r_paren	7	')'
semi	8	';'