Divide $88$ into four parts such as first part known as $a,$ second part $b,$ third part $c,$ and fourth part is $d,$ when $5$ is added to the first part, $5$ is subtracted from the second part, $3$ is multiplied by the third part and the fourth part is divided by $5,$ then all results value are equal. Find the value of $a, b, c$ and $d$ respectively.
a+b+c+d=88
a+5=b-5=3*c=d/5
a+5=3c => a=3c-5
b-5=3c => b=3c+5
d/5=3c => d=15c
=> 3c-5 + 3c+5 + c + 15c = 88
=> 22c = 88
=> c=4
a=3c-5 = 3*4-5 = 7
b=3c+5 = 3*4+5 = 17
d=15c = 15*4 = 60
(a,b,c,d) = (7,17,4,60)
Hence, Option A is the answer
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