Doubt ACE ots 3

Question

Why 50 * 3 and not 50+3 ?

Does every Byte requires different instruction ?

 

Comments

@neeraj33negi @Navneet Kalra 

thanx but my doubt was different. please read the question heading again.

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it depends upon the instruction length if your instruction length comes to 1 byte then yes

if it comes to 2 byte then every instruction requires 2 bytes

reguarding requirement....every instruction will have opcodes and other memory or address references then we will have to find length of instruction and then multiply length with total instructions

Answer 1

• Bits required for registers = log( 24 ) = 5bits
   
• Bits required for instruction = log( 25 ) = 5bits
   
• Instruction size = 5+5+5+5 = 20bits
  since memory is byte addressable, every instruction will be stored in ceil(20/8) = 3 bytes
   
• number of instructions in program = 50
   
• memory required = 50*3 = 150bytes

Answer 2

See each instruction is require 5 bits for opcode ,two 5 bits for source registers and one 5 bit for destination register so making a total of 20 bits which means we need 3 bytes for every instruction now program length is of 50 instructions making a total of 50*3=150 bytes