Triangles ABC and CDE have a common vertex C with the side AB of triangle ABC being parallel to side DE of triangle CDE. If the length of side AB=4 cm and length of side DE=10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is ________ $cm^2$ .
Now here I don’t understand why they have taken BCD and ACE on the same line!
Isn’t this possible?
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