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Show that $p\downarrow q$ is logically equivalent to $\sim(p \vee q).$
in Mathematical Logic
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${\color{Red}{p\downarrow q\equiv\sim(p \vee q)} }$

we can simply use the truth table

$p$ $q$ $p\vee q$ $\sim(p\vee q)$ $p\downarrow q$
T T T F F
T F T F F
F T T F F
F F F T T
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