in Mathematical Logic
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Determine the truth value of each of these statements if the domain for all variables consists of all integers.

  1. $\forall n \exists m (n^2 <m)$
  2. $\exists n \forall m (n <m^2)$
  3. $\forall n \exists m(n+m=0)$
  4. $\exists n \forall m (nm=m)$
  5. $\exists n \exists m (n^2+ m^2 = 5)$
  6. $\exists n \exists m (n^2+m^2 =6)$
  7. $\exists n \exists m (n+m = 4 \wedge n-m =1)$
  8. $\exists n \exists m (n+m = 4 \wedge n-m =2)$
  9. $\forall n \forall m \exists p(p= (m+n)/2)$

 

in Mathematical Logic
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3 Comments

edited by
1 True.(For every integer square we can find a larger integer)
2.True.
3.True.(Since the domain is integer , for n=-m the condition holds)
4.True.(For n=1 , multiplying it with any integer gives the integer itself.)
5.True(4+1=5)
6.False (No such pair exists)
7.False , since n+m=4 . 4 is even , thus n and m both should be even or both should be odd , even - even = even and odd-odd=even . Thus n-m=1 is not possible.
8.True , 3+1=4 and 3-1=2
9.False .
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how option b is false?
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My mistake , it'll be true for negative numbers.
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