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The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of three parallel lines is

  1. $6$
  2. $9$
  3. $12$
  4. $18$
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Answer $D$

Total number of parallel lines $= 4$

Total number of intersecting lines$ = 3$

$\therefore$ Total number of parallelograms possible $$=\binom{4}{2} \times \binom{3}{2} = 6 \times 3 = 18$$

$\therefore D$ is the correct answer.
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Answer $D$

Total number of parallel lines $= 4$

Total number of intersecting lines$ = 3$

$\therefore$ Total number of parallelograms possible $$=\binom{4}{2} \times \binom{3}{2} = 6 \times 3 = 18$$

$\therefore D$ is the correct option.
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