in Calculus recategorized by
514 views
1 vote
1 vote

The value of the definite integral $\int_0^{\pi} \mid \frac{1}{2} + \cos x \mid dx$ is

  1. $\frac{\pi}{6} + \sqrt{3}$
  2. $\frac{\pi}{6} - \sqrt{3}$
  3. $0$
  4. $\frac{1}{2}$
in Calculus recategorized by
by
514 views

2 Comments

$0$ ??
0
0
A  is the answer.
0
0

1 Answer

2 votes
2 votes
Answer is A.

| ½ + cosx | will be positive(>=0) in the interval [0,2pi/3],

while negative(<0) in the interval [2pi/3,pi].

Rest integrating the terms is straight forward.
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true