in Linear Algebra
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3 votes
3 votes

Consider a 3 x 3 real symmetric matrix S such that two of its eigen values are  a ≠ 0 ,  b ≠ 0 with respective Eigen vectors 

[ xxx]  , [ y1 yy] . 

If a ≠ b then x1y1   + x2y2 + x3y3  is

a)   a

b)   b

c)    ab

d)    0

in Linear Algebra
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1 Answer

12 votes
12 votes
Best answer

Let us assume two of eigen values of S are  a ≠ 0 ,  b ≠ 0 with X and Y eigen vectors respectively.

YTX = x1y1   + x2y2 + x3y3

Since X is an eigen vector, therefore, 

SX = aX

YTSX = aYTX   (premultiplying YT on both sides)

(SY)TX = aYTX ( S is a real symmetric matrix)

bYTX = aYTX

(b-a)YTX = 0

YTX = 0   ( given that a != b)

 Eigen vectors X and Y are orthogonal to each other.

Therefore, Correct answer would be (d).

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4 Comments

What is the purpose of taking YTX in the first Line... I mean why to take this in these cases?

1
1

Just to show that we want to calculate YTX.

0
0

How could you write like this ?
Are you trying to summ up the Eigen values of YTX

YTX = x1y1   + x2y2 + x3y3

0
0
awesome explanation
0
0

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