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Recursive enumerable languages are not closed under _________.

  1. Set difference
  2. Complement
  3. Both (A) and (B)
  4. None of the options
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REL is not closed under complement.
A-B = $A\cap( \sim B)$
As Complement is not closed.
Set difference is also not closed.
Option C.

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But intersection of Recursively enumerable and Recursive language is recursively enumerable. Then

A∩(∼B) must be recursively enumerable.
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The answer is C as Recursively Enumerable are closed under every other operation except Set difference and Complementation

Reference: Recursively Enumerable languages

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Except Set difference and Complementation,Recursive enumerable language satisfies all the remaining closure properties.

Answer:opt c
Answer:

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