Link utilization

Question

Bandwidth of a link is 1000 Mbps and RTT is given as 250 micro seconds. If frame size is 500 bits. the utilization(in %age) of channel when stop and wait ARQ used is _________.

Comments

.2 ??

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me too got 0.002

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is ans 0.199 = 0.2 ?

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yes answer given is 0.2, can you post your calculation as answer here.

Answer 1

lu%=(TT/TT+2PT)*100
TT=data/ bandwidth
 =500/1000*10⁶
 =0.5 microsec
 

RTT=250microsec
so LU %=(0.5/0.5+250)
             =0.5/250.5
             =0.00199 *100
             =0.199

            ≅0.2(ans)

Comments

Is it a good practice to round off the answer when necessary, as answer given was 0.2 but answer comming close to 0.2 i.e., 0.199.

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I suggest to use RTT in place of TT + 2 PT when RTT given in Question.