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consider "additive increase multiplicative decrease".one MSS is 512B.If TCP sender don't perceive path as congested

What will be congestion window size after 4RTTs provided congestion window is assigned MSS initially
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8Kb?
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After 4 RTTS:

1->2->4->8->16

So, Congestion Window after 4RTT = 16 * MSS = 16 * 512B = 8KB

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