Simplified expression/s for following Boolean function
$F(A,B,C,D)=\Sigma(0,1,2,3,6,12,13,14,15)$ is/are
Choose the correct answer from the options given below:
hence option D is correct ans
Correct Answer : D
Equivalent Expressions :
1) A'B' + AB + A'CD'
2) A'B' + AB + BCD'
Both b and d are equivalent. Hence Ans is Option D)
The given boolean function can be solved using 4 variable k-map.
In above k-map minterm $(m_0,m_1,m_2,m_3)$ & $(m_{12},m_{13},m_{14},m_{15})$ are essential but for minterm $m_6$ we have $2$ choices; $(m_2,m_6)$ or $(m_{14},m_6)$
So expression are:
So option $(D)$ is correct.
ANS : D
F(A,B,C,D)=Σ(0,1,2,3,6,12,13,14,15)F(A,B,C,D)=Σ(0,1,2,3,6,12,13,14,15)
EQUIVALENT EXPRESSION :
A'B' + AB + A'CD' AND
A'B' + AB + BCD' HENCE OPTION B AND D ARE CORRECT
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