UGC NET CSE | October 2020 | Part 2 | Question: 18

Question

Consider a single-level page table system, with the page table stored in the memory. If the hit rate to TLB is $80\%$, and it takes $15$ nanoseconds to search the $TLB$, and $150$ nanoseconds to access the main memory, then what is the effective memory access time, in nanoseconds?

• A. $185$
• B. $195$
• C. $205$
• D. $175$

Answer 1

EMAT= Hit (TLB access time +Main Memory access time)+Miss(TLB access time+2*Main memory access time )  

 

        = 0.8(15+150)+ 0.2(15+300)

         =132+63 =195 ns

option 2 right ans

Answer 2

0.8(15+150) +0.2(15+150+150)

=132+63

=195 ns

Hence option B is correct✔