Operating System

Question

Disk Access Question 

Answer 1

Total number of blocks K = 64MB/4MB = 16 blocks

Block transfer rate =

32 MB - 20 ms

4MB -  2.5 ms

Total Access time = Seek + RotationalDelay + K*(transfer time for each block)   [Blocks are stored sequentially, therefore they would be in the same cylinder]

= 30 ms + 10ms + 16 *2.5  =  40 ms + 40 ms = 80 ms.

Comments

32 MB in a track- we need 64 MB..

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Yes I did it for 64 MB- 16 blocks of size 4MB.

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http://www.utdallas.edu/~muratk/courses/db08files/parameters_of_disks.pdf sir I followed this reference. Our ppl have worked out on this problem having a slight difference in seek time. https://gateoverflow.in/30488/the-total-time-reuired-to-load-the-program-from-disk?show=30488#q30488