If the size of the logical address space is $2^{m}$ and the page size is $2^{n}$ addressing units, then the high order $\text{m-n bits}$ of a logical address designate the _____________ .
m-n bit n nit
logical address space =2^m. so m bit require to represent the address space
page size=2^n. so n bit require for offset.
so page number =m-n.
Ans is option B.
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