GO Classes 2023 | Weekly Quiz 4 | Question: 2

Answer 1

int x = 5, i = – 7;

• A. ((x>>2)<<2)<=x
  5 in 4-bit system is 0101
  (0101 >>2) <<2   
  ( 0001 ) << 2
  0100  which is 4
  4 <= 5 is True
   
• B. ~1 && 1
  1 : 0001         ~1: 1110       Both are non-zero
  So    ~1 && 1  is True 

100. INT_MIN is the minimum signed number in the system. 
     So in a 4 bit system,  INT_MIN = 1000
     Now,  – INT_MIN = 2’s Complement of INT_MIN = 1000
     Hence,   INT_MIN == – INT_MIN  is True  

500.  −10 < i < −1
     Relational operators ( <, <=, >, >= ) are Left to Right associative 
     So,  (( −10 < – 7 ) < −1 )  
            ( 1 < – 1 )  is False

Comments

Considering 4-bit signed system
1 is 0001  and ~1 is 1110
So when converted to decimal, ~1 is actually -2
Hope that clears the confusion.

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Oh, looking at the question after days, I thought it was about -1 && 1 :P

Correct @mayur_dp

@Arpon Notice that it is a logical AND operator and not bitwise AND, I'm sure you mistook it for bitwise AND

So it's like ~1 && 1

= -2 && 1

= True ^ True (^ is conjunction, every number other than 0 is True)

= True

= 1 (in C Programming)

Since, in C Programming, logical operators return 1 (for true) or 0 (for false) as a result.

 

 

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how is it coming -2? 1110 when converted to decimal is giving -6 right?