in Others edited by
274 views
0 votes
0 votes

Consider the function $f: \mathbb{R}^{2} \rightarrow \mathbb{R}$ defined by $f(x, y)=x^{2}(y-1)$. For $\vec{u}=\left(\frac{1}{2}, \frac{1}{2}\right)$ and $\vec{v}=(3,4)$, the value of the limit 

$$ \lim _{t \rightarrow 0} \frac{f(\vec{u}+t \vec{v})-f(\vec{u})}{t} $$

is

  1. $\frac{3}{4}$
  2. $\frac{6}{13}$
  3. $-\frac{1}{2}$
  4. none of the above
in Others edited by
by
274 views

Please log in or register to answer this question.

Related questions