Does the given solution is correct:
When S is symmetric and transitive, if S contain (3,1),(1,3) then (3,3) should also be present form transitivity.
Please verify the solution.
@GateOverflow04 Bro the Relation S is wrong because in the question they said S is symmetric and transitive but S doesnt have (3,3) pair as
( 3 S 1 ),(1 S 3 ) so according to transtive property ( 3 S 3 ) should be present
@ankitgupta.1729 hi
i saw some one calling you "sir” in one of the answers so im also sticking to this convention 😅
yes sir (1,1) should also be present in S
because if we see the other way (1,3) (3,1) so from transitivity (1,1) should be present in S
The best way to solve this question is by taking counter example
EDIT : I forgot to write (a,a) in set S it's from transitive property (a,c),(c,a) so (a,a) should be present in S
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