Question

The hamming distance between the octets of 0xAA and 0x55 is (A) 7 (B) 5 (C) 8 (D) 6

Comments

@Jeetmoni saikia do you mean 0x?

if yes then it is prefix. it is used to indicate the number is being written in hexadecimal format.

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Yes. Why 0x is not converted into binary

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It's just a indicator , not part of the number.

Answer 1

The given codeword is represented in hexadecimal format as $0x$ as a prefix. Perform the EXOR operations between 2 codewords, the number of $1’s$ in the resultant code word is called hamming distance.

$(0XAA)_H=1010  1010$

$\oplus$

$(0X55)_H= 0101  0101$

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                      $(11111111)$

So the hamming distance of the given codeword is $8$

Ref: UGC NET CSE | June 2014

Answer 2

Hamming Distance  = 5 ans

Answer 3

:8

Apply XOR

0xAA = 1010 1010
0x55 = 0101 0101
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0xFF = 1111 1111

 In the resultant code, the number of 1′s shows Hamming Distance