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In order to play basketball,10 childrens at playgorund divide themselves into two teams of 5 each.How many divisions are possible?
in Quantitative Aptitude retagged by
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{ABCD} LETS DIVIDE THEM IN TWO DIVISIONS .....

IF QUESTION IS HOW MANY COMBINATIONS OF 2 OUT OF 4 ...THEN =4C2=6

BUT NOW ITS ASKING DIVISION

AB CD        CD AB (BOTH ARE SAME)

AC BD        BD AC (BOTH ARE SAME)

AD BC       BC AD (BOTH ARE SAME)

THEREFOR 4C2/2=3 NUMBER OF DIVISIONS....THERE ANSWER IS 10C5/2

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divide themselves means - out of 10 any 1 becomes leader and selects 4 for his team out of 9( excluding himself). so total possible division = 9C10C5/ 2.

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10C5/2
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no the answer given is 10C5/2!
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