in Linear Algebra
631 views
0 votes
0 votes

Isn’t the “No of independent rows”= RAnk of matrix?

in Linear Algebra
by
631 views

9 Comments

Yes true .But the question asked number of independent solution means the solution of $AX=0$ has how many independent vectors not the given matrix A has how many independent solution.
0
0

@Kabir5454 Please elaborate how independent solutions and Rank of matrix are related. It seems I am not able to correlate.

0
0

@DAWID15 I recommend you to watch GO class free youtube video of Linear Algebra. Your doubts will clear.

0
0
edited by
Remind Rank-Nullity theorem,

No. of Columns OR No. of Variables = Rank + Nullity.

Here,
Rank = No. of Independent Columns OR No. of Pivot Variables.
Nullity = No. of Free Variables OR No. of Independent Solutions.

So,
1000 = 640 + Nullity
Nullity = 360
2
2

A follow up to @DebSujit ‘s comment

IF they ask for linearly independent solutions in solution of Ax=b => they are asking about the number of free variables

IF they ask for linearly independent rows/colums in A in Ax=b => they are asking about the number of pivots(or Rank)

1
1

@Shubhodeep Correct!

0
0

@DebRC free and independent variable are same.

1
1

@samarpita fixed

0
0
if rank of the matrix is R and  N is the order of the matrix then

in this matrix N-R indpendent  vector  exist or independent solution exist

1000-640=360
0
0

1 Answer

1 vote
1 vote
Number of Linearly Independent columns = Rank

Number of Linearly Independent solutions = Nullity

 

Here n = 1000

rank = 640

Therefore number of free columns/ nullity = 1000-640 = 360 = Number of independent solutions.
Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true