a)
Assume,
H: I play hockey.
S: I am sore.
W: I use the whirlpool.
Premises:
1) H$\rightarrow$S
2) S$\rightarrow$W
3) $\neg$W
Using 1 & 2 by applying Hypothetical Syllogism. we get,
H$\rightarrow$W --------(4)
Using 3 & 4 by applying modes tollens. we get,
$\neg$H
Hence, we can conclude the conclusion is I didn't play hockey.
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b)
Assume,
W(x) : I work on x day.
S(x) : It's sunny on x day.
P(x) : It's partly sunny on x day.
Premises:
1. $\forall_{x}$W(x)$\rightarrow$(S(x)$\vee$P(x))
2. W(M)$\vee$W(F)
3. $\neg$S(T)
4. $\neg$P(F)
Using 1 by applying Universal Instantiation. If Monday is a particular element of the domain. we get
W(M)$\rightarrow$(S(M)$\vee$P(M)) ------(5)
If Friday is a particular element of the domain. we get,
W(F)$\rightarrow$(S(F)$\vee$P(F)) -------(6)
Using 5, 6 & 2 by applying Constructive Dilemma. we get,
(S(M)$\vee$P(M))$\vee$(S(F)$\vee$P(F)) ----(7)
Using 3 & 4 by applying Conjunction Rule. we get,
$\neg$S(T)$\wedge\neg$P(F) ------(8)
Hence, from 7 & 8 we can conclude that the conclusion is $\neg$S(T)$\wedge\neg$P(F) ^ (S(M)$\vee$P(M))$\vee$(S(F)$\vee$P(F)).
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c)
Assume,
I(x) : x is a insect.
L(x) : x has six legs.
D(x) : x is a dragonfly.
S(x) : x is a Spider.
E(x, y) : x eats y.
Premises:
1. $\forall_{x}$(I(x)$\rightarrow$L(x))
2. $\forall_{x}$(D(x)$\rightarrow$I(x))
3. $\forall_{x}$(S(x)$\rightarrow\neg$L(x))
4. $\forall_{x}\forall_{y}$(S(x)$\wedge$D(y)$\rightarrow$E(x,y))
Applying Universal Instantiation on 1,2 & 3. we get,
I(c)$\rightarrow$L(c) ------------(5)
D(c)$\rightarrow$I(c) ------------(6)
S(c)$\rightarrow\neg$L(c)) ------(7)
Using 6 & 5 by applying hypothetical syllogism. we get,
D(c)$\rightarrow$L(c) -----------(8)
we can rewrite 7 as,
L(c)$\rightarrow\neg$S(c)
Using 5 & 7 by applying hypothetical syllogism. we get,
I(c)$\rightarrow\neg$S(c) ----------(9)
Hence, from 8 & 9 we can conclude that the conclusion is "if c is a dragonfly then it has six legs" and "if c is a insect then it is not a spider".
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d)
Assume,
S(x) : x is a student.
I(x) : x has an Internet account.
Premises:
1. $\forall_{x}$(S(x)$\rightarrow$I(x))
2. $\neg$I(H)
3. I(M)
Using 1 by applying Universal Instantiation. If Homer is a particular element of the domain. we get,
S(H)$\rightarrow$I(H) ------(4)
Using 4 & 2 by applying modus tollens. we get,
$\neg$S(H) ----------(5)
Hence, from 5 we can conclude that the conclusion is $\neg$S(H) .
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e)
Assume,
H(x) : x is healthy to eat.
T(x) : x has taste good.
E(x) : You eat x.
Premises:
1. $\forall_{x}$(H(x)$\rightarrow\neg$T(x))
2. H(T)
3. $\forall_{x}$(T(x)$\rightarrow$E(x))
4.$\neg$E(T)
5. $\neg$H(C)
Using 1 by applying Universal Instantiation. If Tofu is a particular element of the domain. we get,
H(Tofu)$\rightarrow\neg$T(Tofu) -----(6)
Using 6 & 2 by applying modus ponnes. we get,
$\neg$T(Tofu) -------(7)
Hence, from 7 we can conclude that the conclusion is "Tofu hasn't taste good".
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f)
Assume,
D : I am dreaming.
H : I am hallucinating.
E : I see elephants running down the road.
Premises:
1. D$\vee$H
2. $\neg$D
3. H$\rightarrow$E
Using 1 & 2 by applying Disjunctive syllogism. we get,
H --------(4)
Using 4 & 3 by applying modus ponnes. we get,
E ------(5)
Hence, from 5 we can conclude that the conclusion is "I see elephants running down the road".