Decomposition is lossy because $\text{XYUV}$ intersection $\text{YZUW} =\mathrm{YU}$ which is NOT a key in either $\text{P}$ or $\text{S}.$
In the decomposition, dependencies are preserved i.e. union of FD set of $\mathrm{P}, \mathrm{S}$ is equivalent to $\mathrm{F}$.
In $\mathrm{P}$, there is no non-prime attribute, so it is in $3 \mathrm{NF}$.
In $\mathrm{S}$, there is no non-prime attribute, so it is in $3 \mathrm{NF}$.
