Given a grammar:
there is a right most derivation S1 → Sc → SAc → SaSbc. Thus, SaSbc is a right sentential form, and its handle is __
Here in the right-sentential form i.e in $SaSbc$, $A$ is replaced by $aSb$ in previous right-sentential form.
So the handle is $A → aSb$
Detailed ans 👉 https://gateoverflow.in/58011/ugc-net-cse-june-2013-part-2-question-22?show=409708#a409708
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