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Given a grammar:

there is a right most derivation S1 → Sc → SAc → SaSbc.
Thus, SaSbc is a right sentential form, and its handle is __

in Compiler Design
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Here in the right-sentential form i.e in $SaSbc$,   $A$ is replaced by $aSb$ in previous right-sentential form. 
 

So the handle is $A → aSb$ 

 

Detailed ans 👉 https://gateoverflow.in/58011/ugc-net-cse-june-2013-part-2-question-22?show=409708#a409708

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