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Consider two TCP connections $\text{A}$ and $\text{B}:$

The RTT for connection $\text{A}$ is $100$ ms while the RTT for connection $\text{B}$ is $200$ ms. Let $\textsf{ssthresh}$ denote the threshold at which the congestion window size evolution switches over from the Slow Start phase to the Congestion Avoidance phase. Both connections have the $\textsf{ssthresh}$ value of $8.$

At time $\mathrm{T}$ seconds, both connections have just had a timeout, and so their window size is set to $1.$ Calculate how many packets each connection is able to send in the next $1$ second (including at time $\mathrm{T}+1$ seconds). Assume that each packet can be transmitted in $0$ time, and that there are no dropped packets for either connection during the interval $[\text{T}, \text{T}+1]$ seconds.

Which of the following options is TRUE?

  1. Connection $\text{A}$ will end up sending $55$ more packets than connection $\text{B}$ in interval $[\text{T}, \text{T}+1]$ seconds.
  2. Connection $\text{B}$ will end up sending $55$ more packets than connection $\text{A}$ in interval $[\text{T}, \text{T}+1]$ seconds.
  3. Connection $\text{A}$ will end up sending $65$ more packets than connection $\text{B}$ in interval $[\text{T}, \text{T}+1]$ seconds.
  4. Connection $\text{B}$ will end up sending $65$ more packets than connection $\text{A}$ in interval $[\text{T}, \text{T}+1]$ seconds.
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Sir plss take this  question on youtube .
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1 Answer

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$1+2+4+8+9+10+11+12+13+14+15=99$ for flow $\mathrm{A}$

$1+2+4+8+9+10=34$ for flow $\text{B}$
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4 Comments

The congestion window should be halved

Reference kurose:

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@GO Classes sir in this after T second the new threshold should be T/2 na ? why we are using old threshold ?

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Why threshold is not halved after the timeout, isn't the new threshold is 4 ?

@GO Classes

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Answer:

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