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5 votes
5 votes

Recall that a Turing machine $\text{T}$ can be represented or 'coded' by an integer $m$. Let us write 'the $m$ th Turing machine' to mean the Turing machine coded by $m$. Which of the following sets is not recursively enumerable?

  1. The set of $m$ such that the $m$ th Turing machine halts on the input $0.$
  2. The set of $m$ such that the $m$ th Turing machine does not halt on the input $0.$
  3. The set of $m$ such that the $m$ th Turing machine halts on the input $m$.
  4. The set of $n$ such that all Turing machines halt on the input $n$.
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1 Answer

3 votes
3 votes

$\mathrm{A}$ is undecidable but recognizable.

$\text{B}$ is unrecognizable.

$\mathrm{C}$ is undecidable but recognizable.

$\mathrm{D}$ is decidable. There is no input $n$, such that ALL TMs halt on $n.$ So, statement in option D is Trivially Not true, hence, decidable. 

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4 Comments

got it sir..
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@Deepak Poonia Sir option A we can think of monotonic property hence it could be REL or NON REL. so how can we tell it is non REL. Can you please tell me where i am thinking wrong?

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@Kanha3112, Option A is RE but Not REC.

Option A is RE because if TM $M$ halts on input $0,$ we can verify it in finite amount of time. 

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